Re: Rounding a number to integer

[Egor Skriptunoff <egor.skriptunoff@...>]

On Sat, Jul 30, 2016 at 4:02 PM, Duane Leslie <parakleta@darkreality.org> wrote:

A fixed version then:

```lua

function rint(x)

    if x ~= x or x < -0x1p+52 or x > 0x1p+52 then

        -- Already an Integer, or NaN, or Inf

    elseif x < 0 then

        x = ((x - 0x1p+52) + 0x1p+52)

    else

        x = ((x + 0x1p+52) - 0x1p+52)

    end

    return math.floor(x)

end

```

One more problem:

> rint(0.50001)
0